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WAEC Further Mathematics 2022 Paper

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Question : 12

Total: 45

Differentiate

\;\frac{5x^{3}+x^{2}}{x}

, x ≠ 0 with respect to x.

10x + 1
10x + 2
x(15x + 1)
x(15x + 2)

Solution:

$\;\frac{5x^{3}+x^{2}}{x}$ → $\;\frac{5x^{3}}{x} + \;\frac{x^{2}}{x}$

5x $^2$ + x

Then dy/dx = 10x + 1

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