8x+mx2−3x−4≡5x+1+3x−4\frac{8x+m}{x^2-3x-4} \equiv \frac{5}{x+1} + \frac{3}{x-4}x2−3x−48x+m≡x+15+x−43
8x+mx2−3x−4\frac{8x+m}{x^2-3x-4}x2−3x−48x+m ≡ 5(x−1)+3(x+4)x2−3x−4\frac{5(x-1)+3(x+4)}{x^2-3x-4}x2−3x−45(x−1)+3(x+4)
multiplying both sides by x2-3x-4
