y2+xy=5y^2 + xy = 5y2+xy=5
By implicit differentiation
=2y dydx+y+x dydx=0=2y\;\frac{dy}{dx}+y+x\;\frac{dy}{dx}=0=2ydxdy+y+xdxdy=0
=2y dydx+x dydx=−y=2y\;\frac{dy}{dx}+x\;\frac{dy}{dx}=-y=2ydxdy+xdxdy=−y
Factor out dydx\;\frac{dy}{dx}dxdy
= dydx(2y+x)=−y=\;\frac{dy}{dx}(2y+x)=-y=dxdy(2y+x)=−y
∴ dydx= −y2y + x\therefore\;\frac{dy}{dx}=\;\frac{-y}{2y\;+\;x}∴dxdy=2y+x−y