Test Index

WAEC Mathematics 2014 Paper

© africaexams.com

Question : 39

Total: 49

The bar chart shows the scores of some students in a test. If one students is selected at random, find the probability that he/she scored at most 2 marks

$\frac{11}{18}$
$\frac{11}{20}$
$\frac{7}{22}$
$\frac{5}{19}$

Solution:

Concept:

Probability is the number of favourable students divided by the total number of students.

Explanation:

"At most 2 marks" means the student scored 0, 1, or 2 marks.

From the bar chart, the frequencies for these scores are

5

,

2

, and

4

.

So, favourable students

= 5 + 2 + 4 = 11

.

The total number of students is

20

.

Therefore,

P(\text{scored at most 2 marks}) = \frac{11}{20}

.

Answer:

Option B:

\frac{11}{20}

© africaexams.com

Go to Question:

Prev Question

Next Question