a = 23\frac{2}{3}32, d = 715\frac{7}{15}157 - 23\frac{2}{3}32
= 7 - 10
= −315\frac{-3}{15}15−3
d = - −15\frac{-1}{5}5−1
T6 = a + 5d
= 23\frac{2}{3}32 + 5(−15\frac{-1}{5}5−1
= 23\frac{2}{3}32 - 1
= 2−33\frac{2-3}{3}32−3
= −13\frac{-1}{3}3−1
