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WAEC Mathematics 2017 Paper

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Question : 28

Total: 49

The roots of a quadratic equation are

\frac{-1}{2}

\frac{2}{3}

. Find the equation.

$6x^2 - x + 2 = 0$
$6x^2 - x - 2 = 0$
$6x^2 + x - 2 = 0$
$6x^2 + x + 2 = 0$

Solution:

(x + $\frac{1}{2}$ ) (n - $\frac{2}{3}$ )

$x^2 - \frac{2}{3^x} + \frac{x}{2} - \frac{1}{3}$

$6x^2 - 4n + 3n - 2 = 0$

$6x^2 - x - 2 = 0$

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