WAEC Mathematics 2018 Paper

Concept:Probability of an event is the number of favourable teams divided by the total number of teams.Explanation:Total number of teams is $25$.From the table, the number of teams that scored exactly $4$ goals is $6$.So, $P(\text{4 goals}) = \frac{6}{25}$.From the table, the number of teams that scored exactly $7$ goals is $3$.So, $P(\text{7 goals}) = \frac{3}{25}$.Scoring $4$ goals and scoring $7$ goals are mutually exclusive events.Therefore, $P(\text{4 or 7 goals}) = P(\text{4 goals}) + P(\text{7 goals})$.This gives $\frac{6}{25} + \frac{3}{25} = \frac{9}{25}$.Answer:$\frac{9}{25}$So, the correct option is A.