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WAEC Mathematics 2018 Paper

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Question : 19

Total: 50

The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at randon scored either 4 or 7 goals.

$\;\frac{9}{25}$
$\;\frac{1}{5}$
$\;\frac{6}{25}$
$\;\frac{2}{5}$

Solution:

Prob. (team scored 4 goals) = Prob. (team scored 7 goals) = $\;\frac{3}{25}$

Hence, probability that a team selected at random scored either 4 or 7 goals;

= $\;\frac{6}{25} + \;\frac{3}{25}$

= $\;\frac{9}{25}$

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