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WAEC Mathematics 2018 Paper

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Question : 20

Total: 50

The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at random scored at most 3 goals.

$\;\frac{3}{25}$
$\;\frac{1}{5}$
$\;\frac{6}{25}$
$\;\frac{2}{5}$

Solution:

Concept:

Probability is the number of favourable outcomes divided by the total number of outcomes.

Explanation:

From the table, the number of teams that scored at most

3

goals is:

3 + 1 + 6 = 10

Total number of teams is

25

.

So, required probability =

\frac{10}{25} = \frac{2}{5}

Answer:

D.

\;\frac{2}{5}

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