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WAEC Mathematics 2018 Paper

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Question : 20

Total: 50

The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at random scored at most 3 goals.

$\;\frac{3}{25}$
$\;\frac{1}{5}$
$\;\frac{6}{25}$
$\;\frac{2}{5}$

Solution:

No. of teams that scored at most 3 goals = 3 + 1 + 6 = 10

Hence, probability that a team selected at random scored at most 3 goals

= $\;\frac{10}{25}$ = $\;\frac{2}{5}$

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