WAEC Mathematics 2018 Paper

$\frac{x}{y}$ = $\frac{1}{4} \div \frac{3}{8}$ = $\frac{1}{4} \times \frac{8}{3}$ = $\frac{2}{3}$

$\frac{y}{z}$ = $\frac{1}{3} \div \frac{4}{9}$ = $\frac{1}{3} \times \frac{9}{4}$ = $\frac{3}{4}$

But,

x = $\frac{2}{5}T_1$, y = $\frac{3}{5}T_1$

y = $\frac{3}{7}T_2$, z = $\frac{4}{7}T_2$

Using y = y

$\frac{3}{5}T_1$ = x = $\frac{3}{7}T_2$

$\frac{T_1}{T_2}$ = $\frac{3}{7}$ x $\frac{5}{3}$ = $\frac{15}{21}$

$T_1 = 15$ and $T_2 = 21$

Thus , x = $\frac{2}{5}$ x 15 = 6

y = $\frac{3}{5}$ x 15 = 9

y = $\frac{3}{7}$ x 21 = 9

z = $\frac{4}{7}$ x 21 = 12

Hence; x : z = 6 : 12

= 1 : 2