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WAEC Mathematics 2018 Paper

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Question : 29

Total: 50

Expression 0.612 in the form

\;\frac{x}{y}

, where x and y are integers and y

\neq

0

$\;\frac{153}{250}$
$\;\frac{68}{111}$
$\;\frac{61}{100}$
$\;\frac{21}{33}$

Solution:

0.612 = $\;\frac{0.612}{1}$ x $\;\frac{1000}{1000}$

= $\;\frac{612}{1000}$

= $\;\frac{153}{250}$

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