log3x+log3(x−8)=2
log3x(x−8)=log39 since 2 = log39
log3 cancels out
⇒ x(x - 8) = 9⇒ x2−8x=9⇒ x2−8x−9=0⇒ x2−9x+x−9=0⇒ x(x - 9) + 1(x - 9) = 0⇒ (x - 9)(x + 1) = 0⇒ x = 9 or x = -1Since we can't have a log of negative numbers,∴ x = 9.