Let p = 23\frac{2}{3}32 and q = −34\frac{-3}{4}4−3
using (y - p)(y - q) = 0
= ( y - 23)\frac{2}{3})32)( y - (−34))=0\frac{-3}{4})) = 04−3))=0
= (y−23)(y+34)y - \frac{2}{3})\left( y + \frac{3}{4}\right)y−32)(y+43) = 0
y2+34y−23y−612=0y^2 + \frac{3}{4}y - \frac{2}{3}y - \frac{6}{12} = 0y2+43y−32y−126=0
y2+112y−12y^2 + \frac{1}{12}y - \frac{1}{2}y2+121y−21 = 0
= multiply through by the l. c. m of 3 and 4 = 12
∴ the quadratic equation is 12y2+y−6=012y^2 + y - 6 = 012y2+y−6=0
