WAEC Mathematics 2024 Paper

Perimeter of a rectangle = 2(L + B) = length of rod = 44 m

The ratio of length to breadth = 7: 4

That is, $\frac{L}{B}$ = $\frac{7}{4}$

So, L = $\frac{7B}{4}$

Perimeter of a rectangle = 2($\frac{7B}{4}$+ B) = 44

Divide through by 2

($\frac{7B}{4}$+ B) = 22

($\frac{11B}{4}$+ B) = 22

cross multiply

11B = 22 x 4 = 88

B = ($\frac{88}{11}$ = 8m.