WAEC Mathematics 2024 Paper

Vol of cylinder = $\pi$r${}^2$H = vol of cone = $\; \frac{1}{3}$$\pi$r${}^2$h

H = height of cylinder and h = height of cone

Let y = radius of cylinder = y, then radius of cone = 2y

$\pi$y${}^2$H = $\; \frac{1}{3}$$\pi$(2y)${}^2$h

y${}^2$H = $\; \frac{1}{3}$4y${}^2$h ( $\pi$ cancels out and cross multiplying)

The ratio of the height of the cylinder to that of the cone = $\frac{\; \text{H} \;}{\; \text{h} \;}$ = $\; \frac{4y^2}{3y^2}$

= $\; \frac{4}{3}$ = 4: 3 (y${}^2$ cancels out )