In the diagram TU‾\overline{TU}TU is a tangent to the circle SPQR at P. If ∠\angle∠PTS = 44º, ∠\angle∠SQP = 35º, find ∠\angle∠PST
∠\angle∠SPT = 35º (alternate segment)
From △\triangle△TSP
44 + ∠\angle∠SPT + ∠\angle∠PST = 180º (sum of angles in a triangle)
∠\angle∠PST = 180 - 44 - 35 = 101º
