Test Index

WAEC Mathematics 2024 Paper

© africaexams.com

Question : 46

Total: 50

The probability that Amaka will pass an examination is

\frac{3}{7}

and that Bala will pass is

\frac{4}{9}

. Find the probability that both will pass the examination.

$\frac{2}{21}$
$\frac{4}{21}$ .
$\frac{5}{21}$
$\frac{9}{21}$

Solution:

Pr(Amaka passes) = $\frac{3}{7}$ , Pr(Bala passes) = $\frac{4}{9}$ .

Pr(both Amaka and Bala pass the exam) = $\frac{3}{7}$ x $\frac{4}{9}$ = $\frac{4}{21}$ .

© africaexams.com

Go to Question:

Prev Question

Next Question