WAEC Physics 2024 Paper

Concept:Maximum potential energy is reached when the body attains its maximum height and all kinetic energy is converted into potential energy.Explanation:Let the initial projection velocity be $y$.At maximum height $h$, the final velocity becomes zero.Using energy conservation, the initial kinetic energy equals the final potential energy.$$\frac{1}{2} m y^2 = mgh$$Cancelling $m$ from both sides gives: $$\frac{1}{2} y^2 = gh$$Solving for $h$:$$h = \frac{y^2}{2g}$$Thus, potential energy is maximum at this height.Answer:$$h = \frac{y^2}{2g}$$Hence, the correct option is C.