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WAEC Physics 2024 Paper

Question : 23

Total: 50

_{\text{rms}}

Solution:

X $_{c}$ = $\;\frac{1}{2\pi FC}$

X $_{c}$ = $\;\frac{1}{2 \times 3.142 \times 60 \times 2 \times 10^{-6}}$

X $_{c}$ = 1326.1192 $\Omega$

I = $\;\frac{\;\text{V}\;}{X_c}$

I = $\;\frac{150}{1326.1192}$ = 0.113A

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